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J Park
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Prove that if matrix A is nilpotent, then I+A is invertible.

So my friend and I are working on this and here is what we have so far.

We want to show that $\exists \, B$ s.t. $(I+A)B = I$. We considered the fact that $I - A^k = I$ for some positive $k$. Now, if $B = (I-A+A^2-A^3+ \cdots -A^{k-1})$, then $(I+A)B = I-A^k = I$. My question is: in matrix $B$, why is the sign for $A^{k-1}$ negative? Couldn't it be positive, in which case we'd get $(I+A)B = I + A^k$?

Thank you.

J Park
  • 117
  • 1
  • 2