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I have two graphs G1 and G2 with the same vertex set. I would like to take the union of G1 and G2 in such a way that if both G1 and G2 contain the same edge, then the union inherits both of those edges, labeled appropriately. Unfortunately, GraphUnion[G1, G2] seems to lump common edges into one. How can I accomplish my goal?

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2 Answers 2

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Update: If EdgeStyle and EdgeLabels for multi-edges are given as lists, we can use the option EdgeShapeFunction to label and style each edge individually:

graphSum = Module[{esf, styles = GroupBy[Flatten[PropertyValue[#, EdgeStyle] & /@ {##}], First -> Last, Flatten], labels = GroupBy[Flatten[PropertyValue[#, EdgeLabels] & /@ {##}], First -> Last, Flatten]}, esf = {Dashing[{}], Text[First[labels[#2] = RotateRight[labels[#2] ]], BSplineFunction[#][1/2]], First[styles[#2] = RotateRight[styles[#2] ]], Arrow[#]} &; GraphComputation`GraphSum[##, VertexLabels -> "Name", EdgeShapeFunction -> esf]] &;

Examples:

ga = Graph[{1 -> 2}, EdgeStyle -> {_ :> Red}, EdgeLabels -> {e_ :> Style[{e, "ga"}, 16, Black, Bold]}]; gb = Graph[{1 -> 2, 1 -> 2, 1 -> 2, 2 -> 3}, EdgeStyle -> {_ :> Green , (1 -> 2) -> {Blue, Orange, Magenta}}, EdgeLabels -> {e_ :> Style[{e, "gb"}, 16, Black, Bold], (1 -> 2) -> Array[Style[{#, DirectedEdge[1, 2], "gb"}, 16, Black, Bold]&, 3]}] ; SetProperty[graphSum[ga, gb], ImageSize -> 800]

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SetProperty[graphSum[ga, ga, ga, gb, gb], {ImageSize -> 800, VertexLabels -> Placed["Name", Center], VertexShape -> Graphics[{EdgeForm[Gray], FaceForm[LightBlue], Disk[{0, 0}, Offset[8]]}], AspectRatio -> 1/3}]

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Original answer:

GraphComputation`GraphSum gives the desired result:

g1 = Graph[{1 -> 2}]; g2 = Graph[{1 -> 2, 2 -> 3}]; GraphComputation`GraphSum[g1, g2, VertexLabels -> "Name", EdgeLabels -> "Name" ]

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SeedRandom[1] ga = RandomGraph[{5, 7}, DirectedEdges -> True, VertexLabels -> "Name", ImageSize -> 300]; gb = RandomGraph[{10, 10}, DirectedEdges -> True, VertexLabels -> "Name", ImageSize -> 300]; Row[{ga, gb, HighlightGraph[GraphComputation`GraphSum[ga, gb, VertexLabels -> "Name", ImageSize -> 500 ], {ga, gb}]}]

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If you have precisely the same vertices in precisely the same order (i.e. VertexList[g1] === VertexList[g2]), then you can just add the adjacency matrices.

g1 = Graph[{1, 2, 3}, {1 <-> 2}]

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g2 = Graph[{1, 2, 3}, {1 <-> 2, 2 <-> 3}]

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AdjacencyGraph[VertexList[g1], AdjacencyMatrix[g1] + AdjacencyMatrix[g2]]

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Alternatively, join the edge lists. If you do this, it does not matter if the vertex lists are ordered the same. They just need to contain the same vertices.

Graph[VertexList[g1], Join[EdgeList[g1], EdgeList[g2]]]

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  • $\begingroup$ Excellent. Is it possible to label the edges in the new graph according to which graph they came from? I.e. to inherit the edge labels that were already assigned in g1 and g2? $\endgroup$ Commented Oct 18, 2018 at 14:11
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    $\begingroup$ @theQman It's quite problematic. Unfortunately, Mathematica does not properly support multigraph properties. It doesn't even say that it doesn't support them, things just go wrong. The one exception is edge weights, which you could "abuse" for this purpose if you wanted to. $\endgroup$ Commented Oct 18, 2018 at 15:49
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    $\begingroup$ @theQman Here's one discussion of the issue.. If you care about multigraphs, I suggest you contact Wolfram Support and ask them to add this feature. The only chance for it to happen is if many people ask for it (to prove that there really is a demand). $\endgroup$ Commented Oct 18, 2018 at 15:51
  • $\begingroup$ Thank you. How about edge coloring? Is it possible to have color the edges according to which graph they came from, instead of using labels? $\endgroup$ Commented Oct 18, 2018 at 17:13
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    $\begingroup$ @theQman The only properties that sort of work are EdgeWeight, EdgeCapacity and EdgeCost. None of the rest do, not even EdgeStyle. There are tricks that can be used to display parallel edges with different colours but they are hacky and inconvenient. You will find many questions about this, e.g. mathematica.stackexchange.com/q/84477/12 $\endgroup$ Commented Oct 18, 2018 at 20:32

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