Timeline for Numerical evaluation of a sum
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
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| Feb 15, 2016 at 14:35 | comment | added | J. M.'s missing motivation | As for the "AlternatingSigns" method, this yields a result good to ~ 80 digits: NSum[(-1)^n/n^3, {n, 1, Infinity}, WorkingPrecision -> 80, AccuracyGoal -> 50, PrecisionGoal -> ∞, Method -> {"AlternatingSigns", "ExtraTerms" -> 100}, NSumTerms -> 100]. | |
| Feb 14, 2016 at 3:01 | history | answered | J. M.'s missing motivation | CC BY-SA 3.0 |