Timeline for Plotting piecewise function with distinct colors in each section
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 24, 2021 at 2:21 | comment | added | Nick Dong | smooth L1. $0.5x^2$, if $\mid x\mid<1$; otherwise $\mid x\mid -0.5$. f = Piecewise[{{0.5 #^2, Abs[#] < 1}, {Abs[#] - 0.5, Abs[#] >= 1}, {Log[#], 2 < #}}] &; works fine with two colors. | |
| Apr 3, 2013 at 9:11 | history | edited | Mr.Wizard | CC BY-SA 3.0 | deleted 9 characters in body |
| Feb 2, 2012 at 4:59 | history | edited | Mr.Wizard | CC BY-SA 3.0 | added 277 characters in body |
| Feb 1, 2012 at 21:36 | vote | accept | mirandaio | ||
| Jan 20, 2016 at 2:31 | |||||
| Feb 1, 2012 at 21:36 | vote | accept | mirandaio | ||
| Feb 1, 2012 at 21:36 | |||||
| Feb 1, 2012 at 20:44 | history | edited | Mr.Wizard | CC BY-SA 3.0 | added 69 characters in body |
| Feb 1, 2012 at 20:11 | history | edited | Mr.Wizard | CC BY-SA 3.0 | added 362 characters in body |
| Feb 1, 2012 at 20:03 | comment | added | David | This plots the functions as zero out of their piecewise domain. You can get rid of this behavior by using Piecewise[{#, {Indeterminate, True}}] instead. However, this assumes that the original Piecewise does not use a True directive already. | |
| Feb 1, 2012 at 19:58 | history | answered | Mr.Wizard | CC BY-SA 3.0 |