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Nov 4, 2016 at 16:07 comment added user64494 @Masacroso: Thank you for the correction.
Nov 4, 2016 at 15:24 comment added user44169 Well, I explicitly said that Im not interested in this answer. And the expression you put here is not equivalent to the definition of the original function. You must use a ceil function of the kind $$\frac1{\lceil x^{-1}-1\rceil}$$ not a floor one. Observe that $\lfloor z\rfloor\neq\lceil z-1\rceil$ for $z$ real.
Nov 4, 2016 at 14:03 history answered user64494 CC BY-SA 3.0