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Apr 13, 2017 at 12:56 history edited CommunityBot
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Dec 16, 2012 at 21:46 history edited Artes CC BY-SA 3.0
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Dec 16, 2012 at 2:30 history edited Artes CC BY-SA 3.0
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Dec 10, 2012 at 2:25 comment added Artes @CBenni You might play around e.g. with this : Table[ Reduce[ Mod[2^n - n, 10^4] == 0 && k 10^(4) < n < (k + 1) 10^(5 - 1), n, Integers], {k, 10}], while for Mod[2^n - n, 10^5] there is only n == 48736.
Dec 9, 2012 at 17:54 comment added CBenni Reduce[ Mod[ 2^n - n, 10^k] == 0 && 10^(k-1) < n < 10^k, n, Integers] gives me the same error for k>=5. But in general, shouldnt this be evaluated almost immediately?
Dec 9, 2012 at 15:57 vote accept CBenni
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Dec 9, 2012 at 15:23 history answered Artes CC BY-SA 3.0