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$\begingroup$ One more thing to add: test[x__Equal] := 1 will work, too (and probably be faster) $\endgroup$

b3m2a1
– b3m2a1

2017-12-21 06:14:55 +00:00
Commented Dec 21, 2017 at 6:14
$\begingroup$ @b3m2a1 - they have different behaviour, however. If the user enters x==y==z, I don't want this to be pattern matched. $\endgroup$

Myridium
– Myridium

2017-12-21 07:01:24 +00:00
Commented Dec 21, 2017 at 7:01
$\begingroup$ Ahh. Okay. I assumed you were only working with a==b type expressions. $\endgroup$

b3m2a1
– b3m2a1

2017-12-21 07:02:19 +00:00
Commented Dec 21, 2017 at 7:02

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