Timeline for 3D interpolation to 'm x n' matrix
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 28, 2018 at 10:16 | history | edited | Henrik Schumacher | CC BY-SA 3.0 | added 483 characters in body |
| Jan 28, 2018 at 10:02 | comment | added | ralph | While earlier it was easy to generate a matrix 'm x n' ('points') so now I do not know how to do it. I just have to use the ReliefPlot[] function to draw a set 'points'. | |
| Jan 27, 2018 at 23:33 | history | edited | Henrik Schumacher | CC BY-SA 3.0 | added 1032 characters in body |
| Jan 27, 2018 at 9:43 | comment | added | ralph | Thank you. We can obtain the sought set: points= Split[Flatten[pts, 1], #1[[1]] == #2[[1]] &][[All,All,3]]; ....There is still a problem with 'Case 2'. | |
| Jan 27, 2018 at 8:20 | history | answered | Henrik Schumacher | CC BY-SA 3.0 |