Revisions to Any built-in function to generate successive sublists from a list?

edited body

edited Dec 18, 2012 at 20:17

 ReplaceList[lst={a, b, c, d},;  ReplaceList[lst,{x__, ___} :> {x}]

Speaking of "common operation":

 Table[lst[[;; i]], {i, Length@lst}]

 ReplaceList[{a, b, c, d}, {x__, ___} :> {x}]

 lst={a,b,c,d};  ReplaceList[lst,{x__, ___} :> {x}]

Speaking of "common operation":

 Table[lst[[;; i]], {i, Length@lst}]

edited body

edited Dec 18, 2012 at 20:12

 ReplaceList[{a, b, c, d}, {x__, ___} -:> {x}]

 ReplaceList[{a, b, c, d}, {x__, ___} -> {x}]

 ReplaceList[{a, b, c, d}, {x__, ___} :> {x}]

answered Dec 18, 2012 at 19:21

 ReplaceList[{a, b, c, d}, {x__, ___} -> {x}]

Return to Answer