Timeline for Precision differences
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 29, 2012 at 19:35 | history | edited | Artes | CC BY-SA 3.0 | added an example where NSum works while Sum does not |
| Dec 29, 2012 at 6:33 | vote | accept | Fred Daniel Kline | ||
| Dec 28, 2012 at 21:57 | history | edited | Artes | CC BY-SA 3.0 | added 77 characters in body |
| Dec 28, 2012 at 20:51 | history | edited | Artes | CC BY-SA 3.0 | added appropriate settings for NSum |
| Dec 28, 2012 at 20:07 | comment | added | Fred Daniel Kline | Sum[(1/k^2 + 1/(k^2 - k)), {k, 2, Infinity}] - Zeta[2] Here I changed the minus to a plus. | |
| Dec 28, 2012 at 19:43 | comment | added | Artes | @FredKline Just evaluate this Sum[1/k^2, {k, Infinity}] - Zeta[2] to understand what I mean. | |
| Dec 28, 2012 at 19:34 | comment | added | Fred Daniel Kline | I misunderstood. Change the $-$ between the two terms to a $+$ to get zeta[2]. | |
| Dec 28, 2012 at 18:59 | comment | added | Fred Daniel Kline | The second one---1/k^2 (but starting with k=1). | |
| Dec 28, 2012 at 18:51 | comment | added | Artes | @FredKline In these both cases NSum cannot very accurately estimate the results. You should better use Sum wherever it would be possible. Which one does converge to Zeta[2] ? | |
| Dec 28, 2012 at 18:40 | comment | added | Fred Daniel Kline | +1, because I replaced the constant one with a sum that converges to one, this might be a pathelogical example. The pronic numbers may converge to one at a different rate than zeta[2] converges. | |
| Dec 28, 2012 at 18:21 | history | answered | Artes | CC BY-SA 3.0 |