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Jan 30, 2013 at 19:13 comment added whuber This is almost the same as the OP's third solution with #~Divisible~..& replaced by IntegerQ. I like how the reference to 15 has been replaced by a conjunction of criteria, which is closer to the problem statement.
Jan 30, 2013 at 19:08 history answered image_doctor CC BY-SA 3.0