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    $\begingroup$ Try Values[PositionIndex[M]] $\endgroup$ Commented Apr 25, 2019 at 21:39
  • $\begingroup$ @Coolwater If there is a unique row, your method will fail. At least one needs to delete if list has length 1 $\endgroup$ Commented Apr 25, 2019 at 22:58
  • $\begingroup$ @Coolwater IMHO, the best answer is lacking so far. Please consider posting PositionIndex as possible solution. $\endgroup$ Commented Apr 26, 2019 at 12:08