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  • $\begingroup$ JimB, do you have any ideia of how to get an histogram from the rateOfChange curve? Other question: reading the paper again, I've notived that the author had fitted the data points with the following equation: Meq+(Mo-Meq) Exp[-t/tau], and the best fitting gave as an output the inset graphic with the distributions of tau, as well as the estimated value of Meq (which was calculated as 1.5). Do you have any ideia on how did they get it? Thanks in advance $\endgroup$ Commented May 2, 2019 at 14:26
  • $\begingroup$ It's not that I don't know how to get a histogram from the rateOfChange curve, it's because you shouldn't. Are you suggesting that the authors converted the "cumulative dataset" (the dataset you give here) to a "non-cumulative dataset" and fit the function Meq+(Mo-Meq) Exp[-t/tau] ? It might be handy to give the reference to the publication. $\endgroup$ Commented May 2, 2019 at 15:49
  • $\begingroup$ By reading the paper, I think so. The data are from experimental acquisition, and in order to test the accuracy of the numerical approach, the authors suggested that the data are fitted by the given (theoretical) equation with Meq=1.5 and with the given Tau distribution. $\endgroup$ Commented May 2, 2019 at 16:04
  • $\begingroup$ Here's the reference: sciencedirect.com/science/article/pii/S0031920106001610. $\endgroup$ Commented May 2, 2019 at 16:05