I want to take the derivative of a function with respect to 't'$ t $ for an arbitrary k number$ k $ number of times at the point$t=0$ $ t = 0 $ using mathematicaMathematica. The
The function is $e^{kt}\times(\frac{\sinh(t/n)}{\cosh(t/n)-a)})$ Where a
$$ f(t) = \frac{\mathrm e^{kt}\sinh(t/n)}{\cosh(t/n) - a}, $$
where $ a $ and n$ n $ are some constants.