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$\begingroup$ Thanks @Mr.Wizard this was the solution I was looking for. But I ran into some strange behavior that I described more in an edit to the original question (it took a lot of space) that I'm sure you know the explanation for. $\endgroup$

Tanner Legvold
– Tanner Legvold

2019-12-30 17:28:43 +00:00
Commented Dec 30, 2019 at 17:28
$\begingroup$ @Tanner Two points. (1) a_.b_ c_ is NOT the same as a_ . b_ c_ because a_. parses as Optional[Pattern[a, _]]. Perhaps I should have written Dot[a_, b_] c_ for robustness. (2) The second definition of $Pre is itself modified by the existing Function; here is a stand-alone example: Function[, Unevaluated[#] /. Dot[a_, b_] c_ :> a.(b c), HoldAll] /. Dot[a_, b_] c_ :> a.(b c) — within the result the left hand side of RuleDelayed is transformed into (a_).(b_ c_) which is the new precedence rather than the original one. $\endgroup$

Mr.Wizard
– Mr.Wizard

2019-12-30 22:02:53 +00:00
Commented Dec 30, 2019 at 22:02

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