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  • $\begingroup$ Is there a way to achieve this without plotting? I guess that will be slow, and I need to compute areas on a lot of large lists. Thanks for your answer. $\endgroup$ Commented Feb 3, 2020 at 23:53
  • $\begingroup$ @JoséD. you can use Interpolation to get two functions and use NIntegrate . $\endgroup$ Commented Feb 3, 2020 at 23:59
  • $\begingroup$ Performance is really important for my usecase, and I feel like there has to be more efficient alternatives (the shapes are just triangles). Anyway thank you so much for your answer, I am accepting it for now. $\endgroup$ Commented Feb 4, 2020 at 0:17
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    $\begingroup$ A slightly simpler form works: {if1, if2} = Interpolation[#, InterpolationOrder -> 1] & /@ lists $\endgroup$ Commented Feb 4, 2020 at 4:50
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    $\begingroup$ @Fraccalo, I did try that; did not help much. However, usingMethod -> {Automatic, "SymbolicProcessing" ->False} did improve timing considerably. $\endgroup$ Commented Feb 5, 2020 at 9:58