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  • $\begingroup$ That's mine, just longer. :-p $\endgroup$ Commented Mar 16, 2013 at 12:43
  • $\begingroup$ @Mr.Wizard Ha, I've just seen now that in the docs for Span it says m[[i;;j;;k]] is equivalent to Take[m,{i,j,k}]. Well, let's say that mine is more readable for novice users. $\endgroup$ Commented Mar 16, 2013 at 12:49
  • $\begingroup$ Indeed it is. I'm just poking fun. :-) $\endgroup$ Commented Mar 16, 2013 at 12:54
  • $\begingroup$ By the way, try your hand at a "Rube Goldberg" solution. I had fun with mine, though it could be considerably more complicated... $\endgroup$ Commented Mar 16, 2013 at 12:55
  • $\begingroup$ I just timed these and Take is slightly faster. +1 for pragmatism. $\endgroup$ Commented Mar 16, 2013 at 13:08