Timeline for Computing the coefficients of series
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 8, 2020 at 19:39 | vote | accept | Broudy | ||
| Oct 8, 2020 at 19:35 | answer | added | Carl Woll | timeline score: 2 | |
| Oct 8, 2020 at 18:43 | comment | added | Broudy | @Carl Woll Yes, this would be sufficient | |
| Oct 8, 2020 at 18:20 | answer | added | Bill Watts | timeline score: 0 | |
| Oct 8, 2020 at 18:08 | comment | added | Carl Woll | You say you want all of the coefficients. I don't know if that is possible. If you want all of the coefficients up to say q^55, that is easy. | |
| Oct 8, 2020 at 17:51 | history | edited | Broudy | CC BY-SA 4.0 | edited body |
| Oct 8, 2020 at 17:51 | comment | added | Broudy | Ah, you are right. But this does not solve my problem. Can you help me? | |
| Oct 8, 2020 at 17:47 | comment | added | flinty | Which when expressed in Mathematic is: q^{n*(n + 1)/2}/QPochhammer[q, q, n] No it is not. You are using curly brackets which are for lists and things, not subexpressions. The correct way is q^(n(n+1)/2)/QPochhammer[q, q, n] | |
| Oct 8, 2020 at 17:05 | review | First posts | |||
| Oct 8, 2020 at 17:26 | |||||
| Oct 8, 2020 at 17:05 | history | asked | Broudy | CC BY-SA 4.0 |