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added 4 characters in body

edited Apr 14, 2013 at 0:14

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You can define

para = Sequence[BoundaryStyle -> Thick, AxesEdge -> {{-1, -1}, {-1, -1}, {-1, -1}}, Boxed -> False]

then use

ParametricPlot3D[{u, v, 0}, {u, 0, 1}, {v, 0, 1}, Evaluate[para]]

Explanation:

Sequence will automatically expand inside of an expression.

In[]:= {1, Sequence[2,3]} Out[]= {1, 2, 3}

Graphics does accept options given as a list (Graphics[{Circle[]}, {Axes -> False, Frame -> True}]), but many other functions won't. So we need to use Sequence.

BoundaryStyle is an option for ParametricPlot3D, but not for Graphics, therefore it can't be given in Show. So we have to pass the options to ParametricPlot3D directly.

ParametricPlot3D has the HoldAll attribute, which means that para needed to be wrapped in Evaluate to make sure that ParametricPlot3D will see the actual options and not the symbol para.

You can define

para = Sequence[BoundaryStyle -> Thick, AxesEdge -> {{-1, -1}, {-1, -1}, {-1, -1}}, Boxed -> False]

then use

ParametricPlot3D[{u, v, 0}, {u, 0, 1}, {v, 0, 1}, Evaluate[para]]

Explanation:

Sequence will automatically expand inside of an expression.

In[]:= {1, Sequence[2,3]} Out[]= {1, 2, 3}

Graphics does accept options given as a list (Graphics[{Circle[]}, {Axes -> False, Frame -> True}]), but many other functions won't. So we need to use Sequence.

BoundaryStyle is an option for ParametricPlot3D, but not Graphics, therefore it can't be given in Show. So we have to pass the options to ParametricPlot3D directly.

ParametricPlot3D has the HoldAll attribute, which means that para needed to be wrapped in Evaluate to make sure that ParametricPlot3D will see the actual options and not the symbol para.

You can define

para = Sequence[BoundaryStyle -> Thick, AxesEdge -> {{-1, -1}, {-1, -1}, {-1, -1}}, Boxed -> False]

then use

ParametricPlot3D[{u, v, 0}, {u, 0, 1}, {v, 0, 1}, Evaluate[para]]

Explanation:

Sequence will automatically expand inside of an expression.

In[]:= {1, Sequence[2,3]} Out[]= {1, 2, 3}

Graphics does accept options given as a list (Graphics[{Circle[]}, {Axes -> False, Frame -> True}]), but many other functions won't. So we need to use Sequence.

BoundaryStyle is an option for ParametricPlot3D, but not for Graphics, therefore it can't be given in Show. So we have to pass the options to ParametricPlot3D directly.

ParametricPlot3D has the HoldAll attribute, which means that para needed to be wrapped in Evaluate to make sure that ParametricPlot3D will see the actual options and not the symbol para.

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answered Apr 14, 2013 at 0:04

Szabolcs

238.9k
32
653
1.3k

You can define

para = Sequence[BoundaryStyle -> Thick, AxesEdge -> {{-1, -1}, {-1, -1}, {-1, -1}}, Boxed -> False]

then use

ParametricPlot3D[{u, v, 0}, {u, 0, 1}, {v, 0, 1}, Evaluate[para]]

Explanation:

Sequence will automatically expand inside of an expression.

In[]:= {1, Sequence[2,3]} Out[]= {1, 2, 3}

Graphics does accept options given as a list (Graphics[{Circle[]}, {Axes -> False, Frame -> True}]), but many other functions won't. So we need to use Sequence.

BoundaryStyle is an option for ParametricPlot3D, but not Graphics, therefore it can't be given in Show. So we have to pass the options to ParametricPlot3D directly.

ParametricPlot3D has the HoldAll attribute, which means that para needed to be wrapped in Evaluate to make sure that ParametricPlot3D will see the actual options and not the symbol para.