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Nov 1, 2020 at 8:41 vote accept anderstood
Nov 1, 2020 at 8:41 history bounty awarded anderstood
Oct 30, 2020 at 4:57 comment added xzczd @anderstood You need to increase points for plotting, try e.g. PlotPoints -> 1000 or MaxRecursion -> 15 :)
Oct 29, 2020 at 15:02 comment added anderstood @AlexTrounev This is pretty classic, plasticity requires a yield criterion $f(\sigma) \leq 0$, the positivity of the plastic flow multiplier (which must be equivalent to the maximum dissipation principle), and a so-called orthogonality condition: no plastic flow if $f<0$, plastic flow only if $f=0$. See e.g. the third part (page 21) of mms2.ensmp.fr/msi_paris/archives-transparents/….
Oct 29, 2020 at 14:54 comment added anderstood @xzczd Try ParametricPlot[{epsisol[t], sigma[t]}, {t, 0, 1000}, AspectRatio -> 1/2] (after integration on {t, 0, 1000} of course).
Oct 29, 2020 at 2:49 comment added xzczd @anderstood Er… what do you mean by "it drifts a little bit"?
Oct 28, 2020 at 15:10 comment added Alex Trounev @anderstood I agree that in this particular realization the model with WhenEvent[] looks better. Also your model of plasticity is not common. Where did you take it?
Oct 28, 2020 at 13:45 comment added anderstood @AlexTrounev Actually I did manage to make it work with regularization by reformulating the problem with sign (sign[x_] = 2/Pi*ArcTan[10000*x]; epsipsol = NDSolveValue[{E1*epsip[t] - sigma[t] == -sigmay*sign[epsip'[t]], epsip[0] == 0}, epsip, {t, 0, 100}]). But I disagree that it is supposed to be better (see my previous comment). It's supposed to be simpler, for sure, but a high cost!
Oct 28, 2020 at 11:03 comment added Alex Trounev @xzczd Now it looks good (+1). The model with regularization supposed to be better but we are not able to compute this problem using it.
Oct 28, 2020 at 9:23 comment added anderstood Your edited solution is quite what I had in mind and is quite robust. It drifts a little bit but that is ok. A word on your previous "continuous" approach: it is often referred to as "regularizing" but it introduces a somehow arbitrary regularizing parameter (k = 10^3 if I remember well), so possibly a new scale. In general this simplification comes with weaknesses, such as the one mentioned by Alex Trounev. Contrary to your solution with WhenEvent, it was not able to handle non-differentiable sigma functions.
Oct 28, 2020 at 3:23 comment added xzczd @AlexTrounev I find another method that gives the correct solution, have a look.
Oct 28, 2020 at 3:22 history edited xzczd CC BY-SA 4.0
added 130 characters in body
Oct 27, 2020 at 15:02 comment added xzczd @Alex Seems that the DAE solver has turned to i.c. epsi[0] == -0.038287, this might be the reason, so this method isn't that good…
Oct 27, 2020 at 13:31 comment added Alex Trounev It looks like your solution not limited by $\pm 0.5$ as solution by Steffen Jaeschke.
Oct 27, 2020 at 5:13 history answered xzczd CC BY-SA 4.0