Timeline for How do I draw a Circular Graph colored like this in Mathematica?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 8, 2013 at 16:07 | history | edited | J. M.'s missing motivation | CC BY-SA 3.0 | deleted 13 characters in body |
| May 26, 2013 at 17:12 | comment | added | Mr.Wizard | @J.M. Thanks, I forgot what I was subtracting from and confused myself. Corrected. | |
| May 26, 2013 at 17:11 | history | edited | Mr.Wizard | CC BY-SA 3.0 | correct color origin |
| May 26, 2013 at 3:48 | comment | added | J. M.'s missing motivation | @R Hall, better to use Hue[#3 - 1/12], as rm suggested in his answer. That way, red exactly corresponds to $\pi/6$. | |
| May 26, 2013 at 3:32 | comment | added | Nothingtoseehere | @MrWizard +1 for a cool solution! The hue angle is off a bit from the example though. Hue[#3 - (2 Pi/5.8)] will fix it. Thanks! | |
| May 26, 2013 at 3:17 | history | edited | Mr.Wizard | CC BY-SA 3.0 | added 2 characters in body |
| May 26, 2013 at 3:11 | history | answered | Mr.Wizard | CC BY-SA 3.0 |