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Mar 30, 2022 at 12:44 comment added John Doty @Roman has hit the heart of the matter: mathematics as practiced by most of us is useful. Sophistry is useless.
Mar 30, 2022 at 10:41 comment added user64494 @Roman: You open an opened door, repeating a part of my answer in other words.
Mar 30, 2022 at 8:00 comment added Roman Technically you are right; in practice, this answer is useless because wrong for all values of $a,b,c$. What the OP wants is an expression that gives the integral in question, and not a counter-factual but "technically correct" mathematical subtlety. "The integral is zero whenever your parameters satisfy a non-satisfiable condition" is not a useful answer; calling it "mathematically correct" does not help in practice.
Mar 30, 2022 at 5:53 comment added user64494 @Roman: Here is a simpler example of such true proposition: if $2+2=5$, then $2+3=6$.
Mar 30, 2022 at 5:23 comment added user64494 @Roman: Master your math. The Mathematica answer claims that the integral equals zero under the certain impossible condition. Don't hesitate to ask for further explanation in need.
Mar 28, 2022 at 8:16 comment added Roman –1: your answer is obviously wrong. A simple With[{a = 0.2, b = 0.3, c = 0.4}, LogPlot[1/((-(a - I b) + (x + I c)^2) (-(a + I b) + (x - I c)^2)), {x, -10, 10}]] shows that the integrand is positive-definite and therefore the integral must be positive for these specific values of $a, b, c$ (which I've picked at random).
Mar 26, 2022 at 13:01 history edited user64494 CC BY-SA 4.0
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Mar 26, 2022 at 12:47 history edited user64494 CC BY-SA 4.0
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Mar 26, 2022 at 12:37 history edited user64494 CC BY-SA 4.0
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Mar 26, 2022 at 12:36 comment added user64494 Please explain the down-vote. What is incorrect in my answer?
Mar 26, 2022 at 12:30 history answered user64494 CC BY-SA 4.0