Timeline for How to define an operator like ⊕？
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 20, 2022 at 16:36 | comment | added | Curious Cat | Thanks. It seems the problem is the indexing [[ ]] due to a__ is CirclePlus[...] and cannot be indexed. | |
| Oct 20, 2022 at 11:13 | comment | added | Daniel Huber | This leads to an infinite recursion. with: (a[[1 ;;-2]][CirclePlus]a[[-1]]) evaluated over and over. | |
| Oct 20, 2022 at 10:27 | vote | accept | Curious Cat | ||
| Oct 20, 2022 at 10:27 | comment | added | Curious Cat | Thanks @Daniel! I overlooked the 2 blanks! I still have one question: why a__\[CirclePlus]b_ := (a[[1 ;;-2]]\[CirclePlus]a[[-1]])\[CirclePlus]b; doesn't work? | |
| Oct 20, 2022 at 7:24 | comment | added | Daniel Huber | Why you do not try it out? Note that c__ has 2 blanks | |
| Oct 19, 2022 at 22:53 | comment | added | Curious Cat | But what if I want to calculate a\[CirclePlus]b\[CirclePlus]c\[CirclePlus]d or even more variables? | |
| Oct 19, 2022 at 19:49 | history | answered | Daniel Huber | CC BY-SA 4.0 |