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  • $\begingroup$ @Penguin Dirk - I thought you should have elaborated! $\endgroup$ Commented Jul 10, 2013 at 13:39
  • $\begingroup$ @PinguinDirk Agree, almost because the thing is the first line shouldn't give us 1 without any assumptions. Also with, not bold at all, assumption that x and y are independent this limit[x,y] is the same as KronockerDelta[x], in values terms ofc. $\endgroup$ Commented Jul 10, 2013 at 13:48