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$\begingroup$ You can improve oddPartsPartitionsOf13 = (n |-> Select[IntegerPartitions[n], OddQ@Length@# &])[13]; by doing IntegerPartitions[13, {1, Infinity, 2}, All] instead to generate partitions of 13 with an odd lengths instead of generating unnecessary partitions and selecting the ones with Select. $\endgroup$

Peter Burbery
– Peter Burbery

2023-08-03 14:00:30 +00:00
Commented Aug 3, 2023 at 14:00
$\begingroup$ Yes, you are right. $\endgroup$

138 Aspen
– 138 Aspen

2023-08-03 14:01:47 +00:00
Commented Aug 3, 2023 at 14:01

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