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  • $\begingroup$ After writing my (updated) answer it seemed strangely familiar. I believe we have a duplicate: (20713) -- please review that Q&A; if you agree this is a duplicate I will close and delete my answer. $\endgroup$ Commented Aug 26, 2013 at 2:15
  • $\begingroup$ @Mr.Wizard yeah the problem is alike. But I have a question. You suggest in the comment to use f @@ # & to get f[i,j]. What if my function is f[parameter1,i,parameter2,j]? $\endgroup$ Commented Aug 26, 2013 at 2:56
  • $\begingroup$ If I understand you would want f[parameter1, #, parameter2, #2]& @@ # & or perhaps better in that case: f[parameter1, #[[1]], parameter2, #[[2]] ]& $\endgroup$ Commented Aug 26, 2013 at 3:01
  • $\begingroup$ @Mr.Wizard Damn! How could I be so stupid. Just a little trick. Why it just can't come into my mind. Thank you, Mr. Wizard $\endgroup$ Commented Aug 26, 2013 at 4:00
  • $\begingroup$ Don't be so hard on yourself. I make lots of mistakes, and miss or forget plenty of good "tricks." $\endgroup$ Commented Aug 26, 2013 at 4:42