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  • $\begingroup$ But how can one retrieve the original value of $7\pi/2$ out of this? $\endgroup$ Commented Feb 21 at 16:56
  • $\begingroup$ @Domen I was suggesting this as a general approach that can be helpful with this type of problem, rather than a complete solution. Clearly, there remains a mod 2 pi uncertainty, but this can be resolved numerically. $\endgroup$ Commented Feb 21 at 17:08