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$\begingroup$ But if I write D[f[x,y],y] and evaluate, I can copy the output (which looks like f^(0,1)) and use that. Mathematica understands that this is a derivative and not a power. $\endgroup$

yohbs
– yohbs

2012-04-01 13:24:55 +00:00
Commented Apr 1, 2012 at 13:24
1

$\begingroup$ @yohbs that's what is displayed not how it is stored internally. As Verbeia said, internally it is Derivative[0,1][f][x,y], but it has a Format, or similar, that makes it displayed as f$^\text{(0,1)}$[x,y]. $\endgroup$

rcollyer
– rcollyer

2012-04-01 13:34:32 +00:00
Commented Apr 1, 2012 at 13:34

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