Timeline for How to read long numbers? [duplicate]
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 6, 2014 at 17:01 | history | closed | m_goldberg bobthechemist ciao Sjoerd C. de Vries Michael E2 | Duplicate of ReadList can't read from file containing high-precision Reals | |
| Apr 5, 2014 at 21:34 | comment | added | ciao | @Mr.Wizard: No, I think it is, but I'm loath to call something a bug publicly without others reproducing/confirming it first. | |
| Apr 5, 2014 at 18:07 | comment | added | Mr.Wizard | @rasher Wait, I think I misunderstood; you think this is not a bug then? | |
| Apr 5, 2014 at 13:52 | review | Close votes | |||
| Apr 6, 2014 at 17:01 | |||||
| Apr 5, 2014 at 7:13 | comment | added | ciao | @Mr.Wizard: Looks like a possible bug in V9... | |
| Apr 5, 2014 at 6:54 | comment | added | Mr.Wizard | Also related: How to convert a string of number into real numbers without precision loss | |
| Apr 5, 2014 at 6:53 | comment | added | Mr.Wizard | In version 7 ReadList["abc.dat", Real] appears to work correctly, yielding: {6.32974339429986413842620080104840*10^-8, -0.0000254959851559626153977549441655316, -0.0000407099633836181102881717011448444}. What output do you get? | |
| Apr 5, 2014 at 6:51 | comment | added | ciao | Related mathematica.stackexchange.com/questions/33498/… | |
| Apr 5, 2014 at 6:28 | answer | added | Coolwater | timeline score: 1 | |
| Apr 5, 2014 at 6:27 | comment | added | ciao | Read as text, then use something like ToExpression[StringReplace[nums, "E" -> "*10^"]] on that list. However, ReadList[...,Number] should handle the Fortran style. | |
| Apr 5, 2014 at 6:18 | history | asked | Orders | CC BY-SA 3.0 |