Timeline for How do you plot the same function with different options over different intervals?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:55 | history | edited | CommunityBot | replaced http://mathematica.stackexchange.com/ with https://mathematica.stackexchange.com/ | |
| Jun 15, 2012 at 14:14 | comment | added | Ben Allgeier | Oh yeah, I meant to take the square root above. Thanks. | |
| Jun 15, 2012 at 13:06 | comment | added | J. M.'s missing motivation | @Ben, no; $\mathrm{hav}(x)=\sin^2\dfrac{x}{2}$. Otherwise, yes; I'm exploiting the fact that $\mathrm{hav}(x)$ is not immediately simplified to more basic trigonometric functions. | |
| Jun 15, 2012 at 12:55 | comment | added | Ben Allgeier | So what really makes this work? Mathematically, Haversine[2x] is equal to Sin[x] on the interval [0, Pi/2]. It looks like plt has the form {Line[], Line[] }. So the plot thinks of it as two different functions still. Is this right? Interesting solution. | |
| Jun 14, 2012 at 22:50 | history | answered | J. M.'s missing motivation | CC BY-SA 3.0 |