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$\begingroup$ Thank you very much for your reply. $\endgroup$

Dimitris
– Dimitris

2014-12-11 15:14:05 +00:00
Commented Dec 11, 2014 at 15:14
$\begingroup$ Because counta[z_] := Count[z, a_, Infinity] gives a smaller Count for Hill1 (130) than for mat1 (158), I thought that using ComplexityFunction -> counta in my Answer above might drive mat1 to Hill1, but it does not. Strange. $\endgroup$

bbgodfrey
– bbgodfrey

2014-12-11 15:34:38 +00:00
Commented Dec 11, 2014 at 15:34
$\begingroup$ I guess that FullSimplify[Expand[Hill1]]; FullSimplify[Expand[mat1]]; FullSimplify[Expand[Hill2]]; FullSimplify[Expand[mat2]]; is the best we can get. Myself, I am pretty satisfied with your answer. $\endgroup$

Dimitris
– Dimitris

2014-12-11 15:43:04 +00:00
Commented Dec 11, 2014 at 15:43

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