Timeline for Can we abuse notation and write equations in differential one-form?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 25, 2021 at 20:55 | answer | added | Michael E2 | timeline score: 3 | |
| Jan 23, 2017 at 15:23 | history | edited | xzczd♦ | edited tags | |
| Jul 31, 2016 at 4:08 | history | edited | J. M.'s missing motivation | edited tags | |
| Feb 18, 2016 at 17:05 | vote | accept | LLlAMnYP | ||
| May 5, 2015 at 16:05 | history | tweeted | twitter.com/#!/StackMma/status/595620346117627905 | ||
| May 5, 2015 at 14:43 | answer | added | LLlAMnYP | timeline score: 18 | |
| May 5, 2015 at 14:00 | comment | added | LLlAMnYP | Well, the feeling of cheatiness was perfectly valid then. I'm certainly not insisting on a solution to automate such irregular and often simply invalid constructs, I'd just like to find a more or less general approach to putting equations from the OP into Mathematica. I slightly generalized your suggestion with this snippet (-dif[(y/x)] == 2 x Tan[y/x] dif[x]) /. {y -> y[x]} /. {dif[g_] -> Dt[g, x]*dif[x]} which should properly handle differentials of arbitrary things, not just x and y | |
| May 5, 2015 at 13:40 | comment | added | LLlAMnYP | Well, my first thought was to put a differrential into a function. \[DifferentialD]y == Log[1 + \[DifferentialD]x]. Then naively you'd expect y==C+x, but your code returns y==C+x Log[2]. But this feels like cheating. I'm exploring options with functions of multiple arguments or higher order equations for the moment. | |
| May 5, 2015 at 13:19 | comment | added | LLlAMnYP | This is essentially a division by $dx$, which is, of course, all, that is needed in this simple example. I'll try to find something more interesting. | |
| May 5, 2015 at 12:51 | history | asked | LLlAMnYP | CC BY-SA 3.0 |