Timeline for How does one define a function that takes vectors as arguments but also derivatives?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 8, 2015 at 20:14 | comment | added | Charlie Parker | @m_goldberg thanks for those links. I am very happy your teaching me how to fish rather than giving me the fish. I will study this up and try to be as good as I can from the foundations up. I knew I had some fundamental misunderstanding but didn't quite know how to deal with it (hence the question). Thanks btw :) | |
| Aug 8, 2015 at 19:11 | answer | added | bill s | timeline score: 1 | |
| Aug 8, 2015 at 19:07 | comment | added | Michael E2 | Note that it actually was runtime when the errors were thrown because you used Set instead of SetDelayed in defining f. | |
| Aug 8, 2015 at 19:04 | answer | added | m_goldberg | timeline score: 2 | |
| Aug 8, 2015 at 18:42 | comment | added | m_goldberg | Differential operators in Mathematica differentiate with respect to variables, which are symbols. c[[1]] is not a symbol; it is the shortcut form of the expression, Part[c, 1], a call to a built-in function. You can not differentiate with respect to that. | |
| Aug 8, 2015 at 18:34 | comment | added | m_goldberg | All your questions waltz around the same issues, indicating that you simply haven't achieved a proper mental model of how Mathematica works. The best advice I can give you at the moment is to take the time to read through the answers to this question, which is expressly designed to help newcomers to get grounded in Mathematica fundamentals. In particular, this answer relevant to what you ask here. | |
| Aug 8, 2015 at 17:38 | history | asked | Charlie Parker | CC BY-SA 3.0 |