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$\begingroup$ Damn, I was about to post this myself... :D $\endgroup$

J. M.'s missing motivation
– J. M.'s missing motivation

2012-08-14 10:22:14 +00:00
Commented Aug 14, 2012 at 10:22
$\begingroup$ For speed I would try: Xip1 = RotateLeft@Xi; Yip1 = RotateLeft@Yi; and Total[u (1 - v) (1 - w) - (1 - u) v w] $\endgroup$

Mr.Wizard
– Mr.Wizard

2012-08-15 00:22:19 +00:00
Commented Aug 15, 2012 at 0:22
$\begingroup$ I'll just note that inPolyQ2 is exactly what you'll end up with if you try to vectorize Sunday's implementation of the winding number algorithm. $\endgroup$

J. M.'s missing motivation
– J. M.'s missing motivation

2017-01-15 14:13:22 +00:00
Commented Jan 15, 2017 at 14:13

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