Timeline for Help with NonLinearModelFit
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 18, 2015 at 14:11 | history | edited | Jean-Philippe Fontaine | CC BY-SA 3.0 | added 259 characters in body |
| Oct 18, 2015 at 3:26 | answer | added | JimB | timeline score: 7 | |
| Oct 18, 2015 at 0:40 | answer | added | Jack LaVigne | timeline score: 6 | |
| Oct 17, 2015 at 21:54 | comment | added | Jean-Philippe Fontaine | I reduced each data point to a set of three quantities, where the last one is the uncertainty on the second one. | |
| Oct 17, 2015 at 21:54 | comment | added | Karsten7 | The fact that all parameters are near 1 is just consequence of using the default start value (1) for all parameters by not specifying other start values. | |
| Oct 17, 2015 at 21:50 | history | edited | m_goldberg | CC BY-SA 3.0 | improved formatting |
| Oct 17, 2015 at 21:31 | history | edited | Jean-Philippe Fontaine | CC BY-SA 3.0 | added more datas |
| Oct 17, 2015 at 21:22 | comment | added | Jean-Philippe Fontaine | well effectively, I agree that maybe the example is too minimal. I have actually more points. I will make a modeification in my question to include more points. The parameters are near 1, and this I don't understand actually... | |
| Oct 17, 2015 at 19:16 | comment | added | JimB | You have 6 data points and 6 parameters (5 fixed effects and the variance). Did you only use 6 data points as part of a minimal example (which needs to be less minimal) or do you really only have 6 data points? In addition, you see that all of the parameters are very near 1.0 which is what (I believe) Mathematica uses as default starting values. That's not a good sign. | |
| Oct 17, 2015 at 16:44 | history | edited | J. M.'s missing motivation | CC BY-SA 3.0 | "data" is already plural ;) |
| Oct 17, 2015 at 16:32 | history | asked | Jean-Philippe Fontaine | CC BY-SA 3.0 |