Timeline for How to discretize a BezierCurve?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Dec 11, 2015 at 11:12 | comment | added | Jason B. | do you get an error when you enter the line funs = BezierFunction /@ Partition[pt, 4, 3, {1, 1}, {}];? I find that the Partition command creates a list whose last element only has one point. I can only get it to work without error if I add [[;;-2]] after the Partition | |
| Oct 29, 2015 at 15:28 | history | edited | xyz | CC BY-SA 3.0 | added 13 characters in body |
| Oct 29, 2015 at 14:59 | history | edited | Szabolcs | CC BY-SA 3.0 | added 54 characters in body |
| S Oct 29, 2015 at 14:53 | history | answered | Szabolcs | CC BY-SA 3.0 | |
| S Oct 29, 2015 at 14:53 | history | made wiki | Post Made Community Wiki by Szabolcs |