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the data is as follows

data = {{{25, 0.0000234834`}, {45, 0.0000127008`}, {65, 0.0000104495`}, {85, 9.68187`*^-6}, {105, 9.3519`*^-6}}, {{25, 0.0000210205`}, {45, 0.0000159071`}, {65, 0.0000148415`}, {85, 0.0000144786`}, {105, 0.0000143227`}}, {{25, 1.74304`*^-6}, {45, 1.74268`*^-6}, {65, 1.74261`*^-6}, {85, 1.74259`*^-6}, {105, 1.74258`*^-6}}, {{25, 4.26787`*^-6}, {45, 3.95165`*^-6}, {65, 3.88582`*^-6}, {85, 3.86343`*^-6}, {105, 3.85382`*^-6}}, {{25, 3.29821`*^-6}, {45, 3.1484999999999996`*^-6}, {65, 3.1174400000000003`*^-6}, {85, 3.1069`*^-6}, {105, 3.10239`*^-6}}, {{25, 2.4761199999999996`*^-6}, {45, 2.4761199999999996`*^-6}, {65, 2.4761199999999996`*^-6}, {85, 2.4761199999999996`*^-6}, {105, 2.4761199999999996`*^-6}}}

and 

ListLogPlot[data]

gives

img

There are some useless digits like "00000" in the tick. How to prevent this situation automatically?

Edit

I found an interesting thing, If you Shift+Enter the Plot again. Then the 00000 are gone and become scientific form.

img2

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    $\begingroup$ I strongly recommend to create a function, like tickFormat by PinguinDirk from decimal places in FrameTicks. Also, in this Q&A there is my comment to other strongly related topics. $\endgroup$ Commented Dec 12, 2013 at 8:56
  • $\begingroup$ @matheorem Yes I would go for PinguinDirk's answer. Perhaps you can automate it if your plots are all more or less similar. $\endgroup$ Commented Dec 12, 2013 at 9:06
  • $\begingroup$ @Kuba: thanks for the flowers :) I've recently been so inactive, I even forgot the answers I posted myself... good thing you are more active and have the overview of the community! $\endgroup$ Commented Dec 12, 2013 at 9:14
  • $\begingroup$ @PinguinDirk No problem, I usually remember answers that taught me something :) $\endgroup$ Commented Dec 12, 2013 at 9:17
  • $\begingroup$ @Kuba @SjoerdC.deVries Thank you for your information! I learned to style ticks. A custom tickformat is useful. $\endgroup$ Commented Dec 12, 2013 at 10:58

1 Answer 1

Reset to default
3
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Why not multiply by 10^6 and then label the Y axes as times 10^-6?

data[[All, All, 2]] = data[[All, All, 2]] 10^6 ListLogPlot[data, AxesOrigin -> {0, 0}, AxesLabel -> {"X-axes", "Y (\!\(\*SuperscriptBox[\(10\), \(-6\)]\))"}]

enter image description here

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  • $\begingroup$ this is a possible way, thank you for your suggestion $\endgroup$ Commented Dec 12, 2013 at 10:59

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