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a(n) = (4n+3)^7.
3

%I #15 Apr 24 2023 02:54:03

%S 2187,823543,19487171,170859375,893871739,3404825447,10460353203,

%T 27512614111,64339296875,137231006679,271818611107,506623120463,

%U 897410677851,1522435234375,2488651484819,3938980639167,6060711605323,9095120158391,13348388671875,19203908986159

%N a(n) = (4n+3)^7.

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (8,-28,56,-70,56,-28,8,-1).

%F a(n) = A004767(n)^7. - _Wesley Ivan Hurt_, Dec 26 2013

%F Sum_{n>=0} 1/a(n) = 127*zeta(7)/256 - 61*Pi^7/368640. - _Amiram Eldar_, Apr 24 2023

%p A016843:=n->(4*n+3)^7; seq(A016843(n), n=0..50); # _Wesley Ivan Hurt_, Dec 26 2013

%t Table[(4n+3)^7, {n, 0, 50}] (* _Wesley Ivan Hurt_, Dec 26 2013 *)

%Y Cf. A004767, A013665.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_