%I #17 Mar 28 2022 07:40:38

%S 1,13841287201,23298085122481,2213314919066161,59604644775390625,

%T 787662783788549761,6582952005840035281,39959630797262576401,

%U 191581231380566414401,766217865410400390625,2654348974297586158321,8182718904632857144561,22902048046490258711521

%N a(n) = (6*n + 1)^12.

%H Vincenzo Librandi, <a href="/A016932/b016932.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13,-78,286,-715,1287,-1716,1716,-1287,715,-286,78,-13,1).

%F From _Amiram Eldar_, Mar 28 2022: (Start)

%F a(n) = A016921(n)^12 = A016922(n)^6 = A016923(n)^4 = A016924(n)^3 = A016926(n)^2.

%F Sum_{n>=0} 1/a(n) = PolyGamma(11, 1/6)/86890185149644800. (End)

%t Table[(6*n + 1)^12, {n, 0, 12}] (* _Amiram Eldar_, Mar 28 2022 *)

%o (Magma) [(6*n+1)^12: n in [0..20]]; // _Vincenzo Librandi_, May 04 2011

%Y Cf. A016921, A016922, A016923, A016924, A016925, A016926, A016927, A016928, A016929, A016930, A016931.

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_