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a(n) = (11*n + 3)^9.
1

%I #18 Dec 16 2025 10:51:03

%S 19683,20661046784,3814697265625,101559956668416,1119130473102767,

%T 7427658739644928,35452087835576229,134217728000000000,

%U 427929800129788411,1195092568622310912,3004041937984268273,6930988311686938624,14893745087865234375,30142252394633171456,57955795548021664957

%N a(n) = (11*n + 3)^9.

%H Paolo Xausa, <a href="/A017433/b017433.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (10,-45,120,-210,252,-210,120,-45,10,-1).

%t (11*Range[0,10]+3)^9 (* _Harvey P. Dale_, Dec 08 2015 *)

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_