login
a(n) = (12*n + 2)^11.
1

%I #16 Dec 19 2025 09:18:09

%S 2048,4049565169664,3670344486987776,238572050223552512,

%T 4882812500000000000,52036560683837093888,364375289404334925824,

%U 1903193578437064103936,8007313507497959524352,28531167061100000000000,89116503268220597577728,250122512189374498985984,642512252044000682756096

%N a(n) = (12*n + 2)^11.

%H Paolo Xausa, <a href="/A017555/b017555.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12,-66,220,-495,792,-924,792,-495,220,-66,12,-1).

%t (12Range[0,20]+2)^11 (* _Harvey P. Dale_, Mar 24 2011 *)

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_