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a(n) = (12*n + 6)^12.
1

%I #24 Dec 23 2025 23:40:44

%S 2176782336,1156831381426176,531441000000000000,30129469486639681536,

%T 614787626176508399616,6831675453247426400256,50714860157241037295616,

%U 282429536481000000000000,1268241794562545318301696,4817904819828488880132096,16012035393449278995173376,47703367363695867545849856

%N a(n) = (12*n + 6)^12.

%H Vincenzo Librandi, <a href="/A017604/b017604.txt">Table of n, a(n) for n = 0..200</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13,-78,286,-715,1287,-1716,1716,-1287,715,-286,78,-13,1).

%p A017604:=n->(12*n+6)^12: seq(A017604(n), n=0..20); # _Wesley Ivan Hurt_, Jan 31 2017

%t (12*Range[0,20]+6)^12 (* _Harvey P. Dale_, May 31 2014 *)

%t Table[(12 n + 6)^12, {n, 0, 20}] (* _Vincenzo Librandi_, May 31 2014 *)

%o (Magma) [(12*n+6)^12: n in [0..10]]; // _Vincenzo Librandi_, May 31 2014

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_