%I #19 Oct 03 2025 18:27:41

%S 15,1,3,1,1,5,1,3,10,3,1,5,1,1,3,1,30,1,3,1,1,5,1,3,10,3,1,5,1,1,3,1,

%T 30,1,3,1,1,5,1,3,10,3,1,5,1,1,3,1,30,1,3,1,1,5,1,3,10,3,1,5,1,1,3,1,

%U 30,1,3,1,1,5,1,3,10,3,1,5,1,1,3,1,30,1,3,1,1,5,1,3

%N Continued fraction for sqrt(249).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_16">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(249)),confrac);

%t ContinuedFraction[Sqrt[249], 100] (* _Paolo Xausa_, Oct 03 2025 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_