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Continued fraction for sqrt(275).
1

%I #18 Jul 08 2025 23:00:42

%S 16,1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,

%T 1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1,

%U 2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1,2,1,1,32,1,1

%N Continued fraction for sqrt(275).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(275)),confrac);

%t ContinuedFraction[Sqrt[275],100] (* or *) PadRight[{16},100,{32,1,1,2,1,1}] (* _Harvey P. Dale_, May 07 2014 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_