1,4

It appears that either a(n+1) = 2 * a(n) or 2 * a(n) - 1, where this alternation takes on the pattern -1, -1, 0, -1, -1, -1, -1, 0, 0, -1, 0, -1, 0, 0, -1, -1, 0, 0, -1, 0, -1, ...

a(n) = A055642(A061482(n)). - Michel Marcus, Mar 13 2023

Cf. A055642, A061482.

Sequence in context: A094373 A213705 A295637 * A166286 A179807 A110113

Adjacent sequences: A061899 A061900 A061901 * A061903 A061904 A061905

nonn,base,more

Asher Auel, May 05 2001

a(23)-a(27) from Sean A. Irvine, Mar 12 2023

approved