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a(n) = 5^n mod 36.
1

%I #35 Sep 22 2025 16:00:38

%S 1,5,25,17,13,29,1,5,25,17,13,29,1,5,25,17,13,29,1,5,25,17,13,29,1,5,

%T 25,17,13,29,1,5,25,17,13,29,1,5,25,17,13,29,1,5,25,17,13,29,1,5,25,

%U 17,13,29,1,5,25,17,13,29,1,5,25,17,13,29,1,5,25,17,13,29,1,5,25,17,13,29

%N a(n) = 5^n mod 36.

%H G. C. Greubel, <a href="/A070383/b070383.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,1).

%F From _R. J. Mathar_, Apr 20 2010: (Start)

%F a(n) = a(n-6).

%F G.f.: ( -1-5*x-25*x^2-17*x^3-13*x^4-29*x^5 ) / ( (x-1)*(1+x)*(1+x+x^2)*(x^2-x+1) ). (End)

%t PowerMod[5, Range[0, 50], 36] (* _G. C. Greubel_, Mar 16 2016 *)

%o (SageMath) [power_mod(5,n,36) for n in range(0,78)] # _Zerinvary Lajos_, Nov 26 2009

%o (PARI) a(n) = lift(Mod(5,36)^n); \\ _Altug Alkan_, Mar 16 2016

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_, May 12 2002