OFFSET
1,2
COMMENTS
The sequence is infinite. To extend it from the first N terms, one seeks a constellation of composite numbers, of the right parity, whose span is no greater than the sum of the first N terms, S(N). There are infinitely many sequences, of consecutive composite numbers, of length S(N)+1 (indeed, any particular length); and each of those contains a sequence of length S(N) with the right parity. One of those must suffice and that puts an upper-bound on the N+1'st term. - Don Reble, Oct 02 2002
LINKS
Sean A. Irvine, Table of n, a(n) for n = 1..1000
CROSSREFS
KEYWORD
nonn
AUTHOR
Amarnath Murthy, Sep 25 2002
EXTENSIONS
More terms from Don Reble, Oct 02 2002
Offset corrected by Sean A. Irvine, Feb 26 2025
STATUS
approved
