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a(n) = n^8*(n^4 + 1)/2.
1

%I #13 Sep 08 2022 08:45:49

%S 0,1,2176,269001,8421376,122265625,1089230976,6923526001,34368126976,

%T 141236291601,500050000000,1569321367801,4458265214976,11649450426601,

%U 28347694082176,64874450390625,140739635838976,291314606493601

%N a(n) = n^8*(n^4 + 1)/2.

%H Vincenzo Librandi, <a href="/A170776/b170776.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13,-78,286,-715,1287,-1716,1716,-1287,715,-286,78,-13,1).

%F G.f.: (x + 2163*x^2 + 240791*x^3 + 5093805*x^4 + 33148194*x^5 + 81265446* x^6 + 81265446*x^7 + 33148194*x^8 + 5093805*x^9 + 240791*x^10 + 2163* x^11 + x^12)/(1-x)^13. - _G. C. Greubel_, Dec 05 2017

%t Table[n^8*(n^4+1)/2,{n,0,20}] (* _Harvey P. Dale_, Nov 09 2011 *)

%o (Magma) [n^8*(n^4+1)/2: n in [0..30]]; // _Vincenzo Librandi_, Aug 25 2011

%o (PARI) for(n=0, 30, print1(n^8*(n^4+1)/2, ", ")) \\ _G. C. Greubel_, Dec 05 2017

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009