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A291622
Number of irredundant sets in the n X n rook complement graph.
3
2, 9, 94, 777, 3286, 10771, 29366, 69873, 149950, 297111, 553114, 980953, 1677014, 2793771, 4584286, 7492065, 12335422, 20688751, 35673698, 63602601, 117391702, 223644675, 437338630, 872239057, 1763820926, 3599298951, 7386070186, 15205369593, 31353128470
OFFSET
1,1
COMMENTS
The irredundant sets are the distinct subsets of the maximal irredundant sets. These are either any subset of vertices in a single row or column or otherwise have cardinality of at most four (see A291623). - Andrew Howroyd, Aug 30 2017
LINKS
Eric Weisstein's World of Mathematics, Irredundant Set
Eric Weisstein's World of Mathematics, Rook Complement Graph
Index entries for linear recurrences with constant coefficients, signature (11,-53,147,-259,301,-231,113,-32,4).
FORMULA
From Andrew Howroyd, Aug 30 2017: (Start)
a(n) = 2*n*(2^n) + (5*n^6 - 21*n^5 + 47*n^4 - 51*n^3 + 8*n^2 - 24*n + 12)/12 for n > 3.
a(n) = 11*a(n-1) - 53*a(n-2) + 147*a(n-3) - 259*a(n-4) + 301*a(n-5) - 231*a(n-6) + 113*a(n-7) - 32*a(n-8) + 4*a(n-9) for n > 12.
G.f.: x*(2 - 13*x + 101*x^2 - 74*x^3 - 1084*x^4 + 3717*x^5 - 7077*x^6 + 9470*x^7 - 7634*x^8 + 3876*x^9 - 1128*x^10 + 144*x^11)/((1 - x)^7*(1 - 2*x)^2). (End)
MATHEMATICA
Table[Piecewise[{{9, n == 2}, {94, n == 3}}, 2 n (2^n) + (5 n^6 - 21 n^5 + 47 n^4 - 51 n^3 + 8 n^2 - 24 n + 12)/12], {n, 20}]
Join[{2, 9, 94}, LinearRecurrence[{11, -53, 147, -259, 301, -231, 113, -32, 4}, {777, 3286, 10771, 29366, 69873, 149950, 297111, 553114, 980953}, 20]]
CoefficientList[Series[(2 - 13 x + 101 x^2 - 74 x^3 - 1084 x^4 + 3717 x^5 - 7077 x^6 + 9470 x^7 - 7634 x^8 + 3876 x^9 - 1128 x^10 + 144 x^11)/((1 - x)^7 (1 - 2 x)^2), {x, 0, 20}], x]
PROG
(PARI) a(n) = if(n<4, [2, 9, 94][n], 2*n*(2^n) + (5*n^6 - 21*n^5 + 47*n^4 - 51*n^3 + 8*n^2 - 24*n + 12)/12); \\ Andrew Howroyd, Aug 30 2017
CROSSREFS
Main diagonal of A384124.
Cf. A291623.
Sequence in context: A365363 A011804 A292467 * A058156 A381984 A011837
KEYWORD
nonn,easy
AUTHOR
Eric W. Weisstein, Aug 28 2017
EXTENSIONS
Terms a(6) and beyond from Andrew Howroyd, Aug 30 2017
STATUS
approved