login
A368339
Take the solution to Pellian equation x^2 - 8*n*y^2 = 1 with smallest positive y and x >= 0; sequence gives a(n) = y, or 0 if n is twice a positive square. A368340 gives values of x.
1
1, 0, 1, 3, 3, 1, 2, 0, 2, 1, 21, 5, 5, 12, 1, 51, 3, 0, 3, 57, 1, 15, 1794, 7, 7, 45, 33, 1, 1287, 2, 4, 0, 4, 2, 15, 1, 215, 3315, 3, 9, 9, 3, 561, 4137, 1, 60, 110532, 245, 5, 0, 5, 255, 1557945, 65, 1, 6, 48, 455, 14127, 11, 11, 207480, 20, 29427, 285, 1
OFFSET
1,4
LINKS
Carlos Rivera, Problem 88. Follow-up to problem 63, The Prime Puzzles & Problems Connection.
FORMULA
a(n) = A002349(8*n).
a(n) = sqrt((A368340(n)^2 - 1)/(8*n)).
a(A000217(n)) = 1, n >= 1.
EXAMPLE
For n = 1, 2, 3, 4, 5 solutions are (x,y) = (3, 1), (1, 0), (5, 1), (17, 3), (19, 3).
PROG
(PARI) pellsolve(n)={if(issquare(n/2), return(0), q=bnfinit('x^2-8*n, 1); i=-1; until(y&&x==floor(x)&&y==floor(y)&&x^2-8*n*y^2==1, f=lift(q.fu[1]^i); x=abs(polcoeff(f, 0)); y=abs(polcoeff(f, 1)); i++); return(y))};
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
STATUS
approved